If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( y )
y+3 = 0
y+4 = 0
y^2+7*y+12 = 0
y+3 = 0
y+3 = 0
y+3 = 0 // - 3
y = -3
y+4 = 0
y+4 = 0
y+4 = 0 // - 4
y = -4
y^2+7*y+12 = 0
y^2+7*y+12 = 0
y^2+7*y+12 = 0
DELTA = 7^2-(1*4*12)
DELTA = 1
DELTA > 0
y = (1^(1/2)-7)/(1*2) or y = (-1^(1/2)-7)/(1*2)
y = -3 or y = -4
y in (-oo:-4) U (-4:-3) U (-3:+oo)
y/(y+4)+(8*y+28)/(y^2+7*y+12) = 4/(y+3) // - 4/(y+3)
y/(y+4)+(8*y+28)/(y^2+7*y+12)-(4/(y+3)) = 0
y/(y+4)+(8*y+28)/(y^2+7*y+12)-4*(y+3)^-1 = 0
y/(y+4)+(8*y+28)/(y^2+7*y+12)-4/(y+3) = 0
y^2+7*y+12 = 0
y^2+7*y+12 = 0
y^2+7*y+12 = 0
DELTA = 7^2-(1*4*12)
DELTA = 1
DELTA > 0
y = (1^(1/2)-7)/(1*2) or y = (-1^(1/2)-7)/(1*2)
y = -3 or y = -4
(y+4)*(y+3) = 0
y/(y+4)+(8*y+28)/((y+4)*(y+3))-4/(y+3) = 0
(y*(y+3))/((y+4)*(y+3))+(8*y+28)/((y+4)*(y+3))+(-4*(y+4))/((y+4)*(y+3)) = 0
y*(y+3)-4*(y+4)+8*y+28 = 0
y^2+11*y-4*y-16+28 = 0
y^2+7*y+12 = 0
y^2+7*y+12 = 0
y^2+7*y+12 = 0
DELTA = 7^2-(1*4*12)
DELTA = 1
DELTA > 0
y = (1^(1/2)-7)/(1*2) or y = (-1^(1/2)-7)/(1*2)
y = -3 or y = -4
(y+4)*(y+3) = 0
((y+4)*(y+3))/((y+4)*(y+3)) = 0
((y+4)*(y+3))/((y+4)*(y+3)) = 0 // * (y+4)*(y+3)
(y+4)*(y+3) = 0
( y+3 )
y+3 = 0 // - 3
y = -3
( y+4 )
y+4 = 0 // - 4
y = -4
y in { -3}
y in { -4}
y belongs to the empty set
| -2+r=7-r+1 | | -7(7v+2)+8=-251 | | AD=3x+4 | | 3b+7+2(4b)= | | 19+3j=16 | | 17-8x=-33 | | 7x-82=-222 | | 4/7R=20 | | -8t-3t+2=-5t+6t | | 3(3+6x)-5=40 | | 2x+3-x=5-x | | 13x+7(3x+1)=63 | | 1=n/2-1 | | 10(v+1)-4v=3(2v+3)-15 | | -5x-93=2x+26 | | 110y=15y | | 10+3x-2x=-1 | | -4(1+8x)=-196 | | 6y+12=4y+28 | | 5+2z=7 | | 6-2x=5x-9x+12-6 | | 127+13x=3x-93 | | -4(1+5b)=116 | | c=7(y-1) | | -11=1w | | 14-3k=11 | | 5[8-(7x-6)]+4x=0 | | 3/9z=82 | | 9(6+u)-2u=100 | | x-1y=5 | | x=26-3x | | y+6=2(x+5) |